Question

factorise using suitable identity : 8x³-64y³-48x²+96xy²
pls fast​

Answer 1

Answer:

Factor out 8 from the expression..

→ 8(x³ - 8y³)

Using a³-b³= (a-b)(a²+ab+b²), factor out the expression...

→8(x-2y)(x²+2xy+4y²)

Answer 2

Answer:

$(2x-4y)^{3}$

Step-by-step explanation:

(2x)^3 - 3(2x)^2(-4y)+3(2x)(-4y)^2-(4y)

identity = (a-b)^3