Question

Factorise using suitable identity.

8x³+y³+27z³-18xyz​

Answer 1

Answer:

$(2x \: + \: y \: \: + 3z ) 3$

Answer 2

Answer:

$We \: need \: to \: apply \: this \: formula$

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz = (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx)$

Factorise : 8x³+y³+27z³-18xyz

Step-by-step explanation:

8x³+y³+27z³-18xyz

$= \: {(2x)}^{3} + {y}^{3} + {(3z)}^{3} - 3(2x)(y)(3z)$

$=\:(2x + y + 3z) ( \: ( {2x}^{2} ) + {y}^{2} + {(3z)}^{2} - (2x)(y) - (y)(3z) - (2x)(3z) \: )$

$= (2x + y + 3z)( {4x}^{2} + {y}^{2} + {9z}^{2} - 2xy - 3yz - 6xz)$