factorise using suitable identity (8y+4)(8y+3)
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Question:-
Factorise using suitable identity (8y+4)(8y+3).
Answer:-
Using the identity,
(x+a)(x+b)=x²+(a+b)x+ab
Here,
x= 8y
a= 4
b= 3
(8y+4)(8y+3)
= (8y)² + (4+3)8y + (4×3)
= 64y² + 96y + 12
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