Math, asked by theandelshow, 5 months ago

factorise using suitable identity (8y+4)(8y+3)​

Answers

Answered by itscandycrush
2

Answer:

Question:-

Factorise using suitable identity (8y+4)(8y+3).

Answer:-

Using the identity,

(x+a)(x+b)=x²+(a+b)x+ab

Here,

x= 8y

a= 4

b= 3

(8y+4)(8y+3)

= (8y)² + (4+3)8y + (4×3)

= 64y² + 96y + 12

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