factorise using suitable identity 9a sqaure - 30 a + 25
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Simplify the following:
9 a^2 - 30 a + 25
Factor the quadratic 9 a^2 - 30 a + 25. The coefficient of a^2 is 9 and the constant term is 25. The product of 9 and 25 is 225. The factors of 225 which sum to -30 are -15 and -15. So 9 a^2 - 30 a + 25 = 9 a^2 - 15 a - 15 a + 25 = 3 a (3 a - 5) - 5 (3 a - 5):
3 a (3 a - 5) - 5 (3 a - 5)
Factor 3 a - 5 from 3 a (3 a - 5) - 5 (3 a - 5):
(3 a - 5) (3 a - 5)
(3 a - 5) (3 a - 5) = (3 a - 5)^2:
Answer: |
| (3 a - 5)^2
9 a^2 - 30 a + 25
Factor the quadratic 9 a^2 - 30 a + 25. The coefficient of a^2 is 9 and the constant term is 25. The product of 9 and 25 is 225. The factors of 225 which sum to -30 are -15 and -15. So 9 a^2 - 30 a + 25 = 9 a^2 - 15 a - 15 a + 25 = 3 a (3 a - 5) - 5 (3 a - 5):
3 a (3 a - 5) - 5 (3 a - 5)
Factor 3 a - 5 from 3 a (3 a - 5) - 5 (3 a - 5):
(3 a - 5) (3 a - 5)
(3 a - 5) (3 a - 5) = (3 a - 5)^2:
Answer: |
| (3 a - 5)^2
fjgjgtt:
tell me what that upperside arrow mean
raised to the power
eg X^2 =X²
it means sqaure
nah
bol
its like x^3= x³
properly tell
x^y = x pe power y
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I hope all steps are clear
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