Question

Factorise using suitable identity:

i) x²+ 2xy + y² – 100

Kindly tell with explanation ​

Answer 1

Answer:

6xy-100=94

so the answer is 94xy

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Answer 2

i) x²+2xy+y²-100

={(x)²+2×x×y+(y)²} - 100 {x²+2xy+y² is the expanded form of (x+y)²

=(x+y)²-(10)²

Now using the identity a²-b² = (a+b)(a-b)

In this case we will take (x+y) as a and 10 as b

(x+y)²-(10)²

= (x+y+10)(x+y-10) (Ans)

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