Question

factorise using suitable identity x^2+2xy+y^2-100​

Answer 1

Answer:

x²+2xy+y²-100

(x+y)²-100 [using Identity– (a+b)²=a²+b²+2ab]

(x+y)²-10²

(x+y+10)(x+y-10).[using identity–(a+b)(a-b)=a²-b²]

answer: (x+y-10)(x+y+10)

Step-by-step explanation:

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Answer 2

Answer:

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