Math, asked by abhaykumarsingh30, 1 year ago

factorise using suitable identity x^3-8y^3​

Answers

Answered by hozefancc
2

Step-by-step explanation:

Here's your answer

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Answered by sapnaopjs
0

Answer:

(x-2y)(x^2+2xy+4y^2)

Step-by-step explanation:

Identity - (a-b) (a^2+ab+b^2)

(x-2y)(x^2+x*2y+2y^2)

= (x-2y)(x^2+2xy+4y^2)

Hope it's helpful!!

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