factorise using suitable identity
x4 - ( y+3 )4
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If the question is
x⁴-(y+3)⁴
(x²)² - {(y+3)²}²
{(x²-(y+3)²} {x²+(y+3)²}
{(x+y+3)(x-y-3)} {x²+y²+9+12y}
I hope this much will help you
x⁴-(y+3)⁴
(x²)² - {(y+3)²}²
{(x²-(y+3)²} {x²+(y+3)²}
{(x+y+3)(x-y-3)} {x²+y²+9+12y}
I hope this much will help you
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