Question

Factorise using the factor theorem

▪ x³-x²-4x+4x​

Answer 1

Step-by-step explanation:

Appropriate question:-

• x³- x²-4x +4

Solution:-

$\tt \to {x}^{3} - {x}^{2} - 4x + 4 \\ \tt \to {x}^{2} (x -1) - 4(x -1) \\ \tt \to( {x}^{2} - 4)(x - 1)$

$\tt \red {Identity - }$

$\tt \green{ {a}^{2} - {b}^{2} =( a + b)(a - b)}$

$\tt So,( {x}^{2} - 4)(x - 1) = ( {x}^{2} - {2}^{2} )(x - 1) \\ \tt = (x + 2)(x - 2)(x - 1)$

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Answer 2

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