factorise using the identities
(Step by step)
Attachments:
Answers
Answered by
4
Answer:
9x²y²+6xyz+z²
(3xy)²+2×3xy×z+(z)²
using identity
a²+2ab+b²=(a+b)²
=(3xyz+z)²
=(3xyz+z)(3xyz+z)
please mark my ans as brainleast
please mark my ans as 5 star
Answered by
1
Answer:
ok
ok
ok
ok
okokokokokokokokokokokokokokokokokookokokokokook
Step-by-step explanation:
Similar questions