Question

factorise using this identity
(a+b)=a^2+2ab+b^2
4x^2+24xy+36y^2​

Answer 1

Answer:

$4x {}^{2} + 24xy + 36y {}^{2} \\ > (2x) {}^{2} + 2 \times 2x \times 6y + (6y) {}^{2} \\ > (2x + 6y) {}^{2} \\ > (2x + 6y)(2x + 6y)$

hope this helps

wishing you good luck

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