Question

factorise

(vii) (l + m)2 - 4lm
(Hint: Expand (l + m)? first)

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Answer 1

Answer:

Answer is (1-m square)

Step-by-step explanation:

Thank you

Answer 2

Answer:

(l-m)²

Step-by-step Explanation:

⇒ (l+m)²-4lm

Now we can see that there's an identity is applicable which is (a+b)²=a²+b²+2ab, where l=a and m=b

⇒ (l+m)²-4lm

⇒ (l)²+(m)²+2(L)(m)-4lm

⇒ l²+m²+2Lm-4lm

⇒ l²+m²-2lm

Now we can again apply identity a²+b²-2ab=(a-b)², where l=a and b=m

⇒ (l-m)²

Hence factorised!

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