Math, asked by sibanitanti75, 7 days ago

factorise: viii) x3 + 3x2 - 7x - 6
please answer my question​

Answers

Answered by mishravijay0117
0

STEP

1

:

Equation at the end of step 1

(((x3) + 3x2) - 7x) - 6

STEP

2

:

Checking for a perfect cube

2.1 x3+3x2-7x-6 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3+3x2-7x-6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -7x-6

Group 2: x3+3x2

Pull out from each group separately :

Group 1: (7x+6) • (-1)

Group 2: (x+3) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

2.3 Find roots (zeroes) of : F(x) = x3+3x2-7x-6

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is -6.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1 ,2 ,3 ,6

Let us test ....

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms

In our case this means that

x3+3x2-7x-6

can be divided with x-2

Polynomial Long Division :

2.4 Polynomial Long Division

Dividing : x3+3x2-7x-6

Quotient : x2+5x+3 Remainder: 0

Trying to factor by splitting the middle term

2.5 Factoring x2+5x+3

The first term is, x2 its coefficient is 1 .

The middle term is, +5x its coefficient is 5 .

The last term, "the constant", is +3

Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3

Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is 5 .

-3 + -1 = -4

-1 + -3 = -4

1 + 3 = 4

3 + 1 = 4

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

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