Question

factorise with full steps

Answer 1

Howdy!!

your answer is ---

Given,
$x + \frac{1}{x} = 3$

now,

we have,

${x}^{4} + \frac{1}{ {x}^{4} } \\ = {( {x}^{2} + \frac{1}{ {x}^{2} } ) }^{2} - 2$

= [(x+1/x)^2 - 2]^2 -2

= ( 3^2 -2 )^2 -2

= ( 9 - 2) ^2 - 2

= 7^2 - 2

= 49 - 2

= 47

hope it help you

Answer 2

Solution:-

given by:-
$x + \frac{1}{x} = 3 \\ {(x + \frac{1}{x}) }^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 9 - 2 = 7 \\ {( {x }^{2} + \frac{1}{ {x}^{2} } )}^{2} = {x}^{4} + \frac{1}{ {x}^{4} } + 2 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 49 - 2 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 47 \\ \\ i \: hope \: its \: is \: helpfull \: for \: u$