Question

factorise with solution
${2x}^{3} + {9x}^{2} + 10x + 3$

Answer 1

hii,I wish my answer will help you out.....
Firstly, let x=-1
p[-1]=2X[-1]^3+9-10+3
-2+9-10+3
7-10+3
=0
This tells that [x+1] is a factor of p[x]
Now,divide [2x^3+9x^2+10x+3] by [x+1]
You will get 2x^2+7x+3
And,by the method of middle term splitting....
you will get [2x+1][x+3]
So,the final answer will be [x+1][2x+1][x+3]...