factorise with steps
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Answered by
0
hi,
using (a-b) ^2=(a^2)-2(a)
(b)+(b^2)
here a=a^2 and b=b^2
a^4-2(a^2)(b^2)+b^4
=(a^2)^2-2(a^2)(b^2)+(b^2)^2
=(a^2-b^2)^2
hope, it helps
using (a-b) ^2=(a^2)-2(a)
(b)+(b^2)
here a=a^2 and b=b^2
a^4-2(a^2)(b^2)+b^4
=(a^2)^2-2(a^2)(b^2)+(b^2)^2
=(a^2-b^2)^2
hope, it helps
Answered by
1
Hi ,
a⁴ - 2a²b² + b⁴
= ( a² )² - 2 × a² × b² + ( b² )²
= ( a² - b² )²
= ( a² - b² ) ( a² - b² )
= ( a + b ) ( a - b ) ( a + b ) ( a - b )
I hope this helps you.
:)
a⁴ - 2a²b² + b⁴
= ( a² )² - 2 × a² × b² + ( b² )²
= ( a² - b² )²
= ( a² - b² ) ( a² - b² )
= ( a + b ) ( a - b ) ( a + b ) ( a - b )
I hope this helps you.
:)
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