Question

factorise with suitable Identities
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Answer 1

GIVEN :-

• 9x² + 6xy + y².

TO FACTORISE :-

• 9x² + 6xy + y²

FACTORISATION :-

➬ 9x² + 6xy + y²

➬ (3x)² + 2 × 3x × y + (y)²

☯ By using Identity (a + b)² = a² + 2ab + b².

➬ (3x + y)²

➬ (3x + y)(3x + y)

➬ (3x + y)(3x + y)

Hence Factorised.

ADDITIONAL INFORMATION :-

☦ Algebraic Identity's

➳ ( x + y )² = x² + 2xy + y²

➳ ( x - y )² = x² - 2xy + y²

➳ ( x - y ) ( x -y ) = ( x - y )²

➳ ( x + y ) ( x + y ) = ( x + y )²

➳ x² - y² = ( x + y ) ( x - y )

➳ ( x + y + z )² = x² + y² + z² + 2xy + 2yz + 2zx.

➳ ( x + a ) ( x + b ) = x² + ( a + b)x + ab

Answer 2

Factorise :-

9x² + 6xy + y²

Answer :-

Formula used :-

• (a + b)² = a² + 2ab + b²

→ (3x)² + 2 × 3x × y + (y)²

→ (3x + y)²

→ (3x + y) (3x + y)

.°. The answer is (3x + y) (3x + y)...