Question

Factorise with suitable identity 8a^3+b^3+12a^2b+6ab^2

Answer 1

HELLO DEAR,


8a³ + b³ + 12a²b + 6ab²

(2a)³ + b³ + 3(2a)b(2a + b)

(2a + b)³
∴ [ (a + b)³ = a³ + b³ + 3ab(a + b)



I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Heya ✋

Let see your answer !!!!!

$8a ^{3} + b ^{3} + 12a ^{2}b + 6ab ^{2} \\ we \: apply \: this \: identity \: here$
$(a + b) ^{3} = a ^{3} + b ^{3} + 3a ^{2}b + 3ab ^{2}$


$= (2a) ^{3} + (b) ^{3} + 3 \times (2a) ^{2} \times b + 3 \times 2a \times b ^{2} \\ \\ = (2a + b) ^{3} \\ \\ = (2a + b)(2a + b)(2a + b)$








Thanks :)))))