Question

factorise (x+1)^2-16=0​

Answer 1

Step-by-step explanation:

${(x + 1)}^{2} - 16 = 0$

${x}^{2} + 1 + 2x - 16 = 0$

${x}^{2} + 2x - 15 = 0$

${x}^{2} + 5x - 3x - 15 = 0$

$x(x + 5) - 3(x + 5) = 0$

$(x - 3)(x + 5) = 0$

$x = 3 \: or - 5$

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