Question

factorise ( x + 1 )² - 4x pls do explain​

Answer 1

Answer:

Here is your answer

⇒$(x+1)^2-4x$

⇒you can see over there that $(x+1)^2$ is in the form of $(a+b)^2$

So now the formula is

⇒$(a+b)^2=a^2+2ab+b^2$

appling that formula to $(x+1)^2$

⇒$(x+1)^2=x^2+2(x)(1)+(1)^2$

so now bring it into final equation that is

⇒$(x)^2+2(x)(1)+(1)^2-4x$

⇒$x^2+2x+1-4x$

⇒$x^2+2x-4x+1$

⇒$x^2-2x+1$

So you have got a equation now,we have to separate

⇒$x^2-x-x+1$

Now factorise

⇒$x(x-1)-1(x-1)$

⇒$(x-1)(x-1)$ is the equation

⇒$x-1=0$                   or              ⇒$x-1=0$

⇒$x=1$                          or             ⇒$x=1$

So finally your answer is

⇒$x=1,1$