Question

factorise (x+1)²-4x Plz tell

Answer 1

${x}^{2} + 2x + 1- 4x \\ {x}^{2} - 2x + 1 \\ {x}^{2} - x - x + 1 \\ x(x - 1) - 1(x - 1) \\ x - 1 = 0 \\ x = 1$

Answer 2

Answer:

(x-1)^2

Step-by-step explanation:

(x)^2+2*x*1+(1)^2-4x

(x)^2+2x+1-4x

(x)^2-2x+1

(x-1)^2