Factorise
(X+1)^2 - (y-1)^2
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Answered by
6
Hey
Here is your answer,
By using the identity ,
(a+b)^2 = a^2 + b^2 + 2ab
(a-b)^2 = a^2 + b^2 - 2ab
(X+1)^2 - (y-1)^2
= X^2 + 1 + 2x - ( y^2 + 1 -2y)
= X^2 + 1 + 2x - y^2 - 1 + 2y
= X^2 -y^2 +2x + 2y
= (X+y) ( x -y) + 2(x+y)
= (X+y) {(x-y) + 2}
Hope it helps you!
Here is your answer,
By using the identity ,
(a+b)^2 = a^2 + b^2 + 2ab
(a-b)^2 = a^2 + b^2 - 2ab
(X+1)^2 - (y-1)^2
= X^2 + 1 + 2x - ( y^2 + 1 -2y)
= X^2 + 1 + 2x - y^2 - 1 + 2y
= X^2 -y^2 +2x + 2y
= (X+y) ( x -y) + 2(x+y)
= (X+y) {(x-y) + 2}
Hope it helps you!
Answered by
2
(x + 1)^2=X^2 + 2x +1
(y-1)^2=y^2 -2y+1
(x+1)^2 - (y-1)^2=X^2 + 2x +1-(y^2 -2y+1)
=X^2 + 2x +1-y^2 +2y-1
=X^2-y^2 + 2x +2y
(y-1)^2=y^2 -2y+1
(x+1)^2 - (y-1)^2=X^2 + 2x +1-(y^2 -2y+1)
=X^2 + 2x +1-y^2 +2y-1
=X^2-y^2 + 2x +2y
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