Question

factorise (x+1)³+(x-1)³

Answer 1

(x+1+x-1){(x+1)^2+(x-1)^2-(x+1)(x-1)}
2x{x^2+1+2x+x^2+1-2x-(x^2-1^2)}
2x{x^2+1+2x+x^2+1-2x-x^2+1}
2x{x^2+3}
is your answer

zeroes is
2x=0 or x^2+3=0
x=0,1/√3

Answer 2

Answer:

The factor of $(x+1)^3+(x-1)^3=(2x)(x^2+3)$

Step-by-step explanation:

Given : Expression $(x+1)^3+(x-1)^3$

To find : The factorize of the expression?

Solution :

We know that,

$(a+b)^3=a^3+b^3+3ab(a+b)$

Substituting a=(x+1) and b=(x-1)

$(x+1+x-1)^3=(x+1)^3+(x-1)^3+3(x+1)(x-1)(x+1+x-1)$

$(2x)^3=(x+1)^3+(x-1)^3+3(x^2-1)(2x)$

$8x^3=(x+1)^3+(x-1)^3+6x^3-6x$

$8x^3-6x^3+6x=(x+1)^3+(x-1)^3$

$2x^3+6x=(x+1)^3+(x-1)^3$

$2x(x^2+3)=(x+1)^3+(x-1)^3$

So, The factor of $(x+1)^3+(x-1)^3=(2x)(x^2+3)$