Factorise (x +1)^3 - (x - 1)^3
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(x+1)^3 - (x-1)^3
= [x+1 - (x-1)] [ (x+1)^2 + (x+1)(x-1) +(x-1)^2 ]
= 2 [ 3 x^2 + 1 ]
= [x+1 - (x-1)] [ (x+1)^2 + (x+1)(x-1) +(x-1)^2 ]
= 2 [ 3 x^2 + 1 ]
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