factorise (x+1)^6-(x-1)^6
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Answered by
45
(x + 1)⁶ - (x - 1)⁶
= (x⁶ + 6x⁵ + 15x⁴ + 20x³ + 15x² + 6x + 1 ) - (x⁶ - 6x⁵ +15x⁴ -20x³ + 15x²-6x + 1)
= x⁶ + 6x⁵ + 15x⁴ + 20x³ + 15x² + 6x + 1 - x⁶ + 6x⁵ - 15x⁴ +20x³ -15x² + 6x - 1
= 12x⁵ + 40x³ + 12x
= 4x (3x⁴ + 10x² + 3)
= 4x (x² + 3) (3x² + 1)
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Answer: 4x (x² + 3) (3x² + 1)
Answered by
27
Answer :D
(x + 1)⁶ - (x - 1)⁶
= (x⁶ + 6x⁵ + 15x⁴ + 20x³ + 15x² + 6x + 1 ) - (x⁶ - 6x⁵ +15x⁴ -20x³ + 15x²-6x + 1)
= x⁶ + 6x⁵ + 15x⁴ + 20x³ + 15x² + 6x + 1 - x⁶ + 6x⁵ - 15x⁴ +20x³ -15x² + 6x - 1
= 12x⁵ + 40x³ + 12x
= 4x (3x⁴ + 10x² + 3)
= 4x (x² + 3) (3x² + 1)
.
Answer: 4x (x² + 3) (3x² + 1)
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