Question

Factorise (x+1)(x+3)(x-4)(x-6)+24

Answer 1

Answer:

I re-wrote this as:

(x+1) (x-4) (x+3) (x-6) + 24 = 0

(x2 - 3x -4) (x2 -3x -18) +24 = 0

Now let x2 - 3x = t (where x2 is x-squared)

So the equation becomes:

(t-4)(t-18) + 24 = 0

t2 -22t + 72+24 = 0

t2-22t + 96 = 0

t2 - 16t -6t +95 = 0

(t-16) (t-6) = 0

t = 16,6

x2 - 3x = {16,6}

now its quadratic equation, help yourself :)