Question

factorise x^10+x^2+1 ( question is absolutely correct)​

Answer 1

Answer:

Let x² = y

Let x² = y y^5+y+1

y^5+y+1 = (y^5-y²)+(y²+y+1)

= y²(y³-1)+(y²+y+1)

= y²(y-1)(y²+y+1)(y²+y+1)

= (y³-y²+1)(y²+y+1)

Now, putting y = x² we get,

x^10+x²+1 = (x^6-x⁴+1)(x⁴+x²+1) (Ans)

(Mark as brainlist)

Answer 2

Answer:

✍ Step-by-step explanation:

✏Let x² = y

Let x² = y y^5+y+1

y^5+y+1 = (y^5-y²)+(y²+y+1)

= y²(y³-1)+(y²+y+1)

= y²(y-1)(y²+y+1)(y²+y+1)

= (y³-y²+1)(y²+y+1)

✍ Now, putting y = x² we get,

☞ x^10+x²+1 = (x^6-x⁴+1)(x⁴+x²+1) (Ans)