Math, asked by kaynat87, 11 months ago

factorise x^2 + 1/x^2+2 - 2x -2/x

 \sf{x}^{2}  +  \frac{1}{ {x}^{2} }  +  2 - 2x -  \frac{2}{x}
 <marquee \: behavior> <font \: color = red > help me

Answers

Answered by aditya012
2

Answer:

( x + 1/x)( x + 1/x - 2)

Step-by-step explanation:

x^2 + 1/x^2 + 2 - 2x -2/x

= ( x + 1/x )^2 -2( x + 1/x ) since x^2 + 1/x^2 + 2 is in the form a^2 + b^2 + 2ab = ( a + b)^2

= ( x + 1/x )( x + 1/x - 2 )

Factorisation done here is by :

=> algebric identity a^2 + b^2 + 2ab = ( a + b) ^2

=> taking out the common term which is x + 1/x

Answered by princepc076
4

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