factorise x^2+1/x^2-2-3x-3/x
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Seems your question is --- above
So, X^2+1/x^2-2-3x+3/x
=(x-1/x)^2+2x×1/x-2-3(x-1/x)
Note:-a^2+b^2=(a-b)^2+2ab, here in place of a use x and in place of b use 1/x then, x^2+1/x^2
=(x-1/x)^2+(2x×1/x)
=(x-1/x)^2+2-2-3(x-1/x)
=(x-1)^2-3(x-1/x)
=(x-1/x)(x-1/x-3)
HOPE YOU LIKED IT A LOT!!!
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