Math, asked by Rathore246yashwani, 10 months ago

factorise x^2+1/x^2-2-3x-3/x​

Answers

Answered by mangal007james
1

Seems your question is --- above

So, X^2+1/x^2-2-3x+3/x

=(x-1/x)^2+2x×1/x-2-3(x-1/x)

Note:-a^2+b^2=(a-b)^2+2ab, here in place of a use x and in place of b use 1/x then, x^2+1/x^2

=(x-1/x)^2+(2x×1/x)

=(x-1/x)^2+2-2-3(x-1/x)

=(x-1)^2-3(x-1/x)

=(x-1/x)(x-1/x-3)

HOPE YOU LIKED IT A LOT!!!

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