Question

factorise:
x^2+1/x^2-2-3x+3/x​

Answer 1

Step-by-step explanation:

• x^2 +1/x^2 -2-3x+3/x
• -{\frac{1}{x})(x-\frac{1}{x}-3)
• Step-by-step explanation:
• The given equation is:
• x^2+{\frac{1}{x^2}}-2-3x+\frac{3}{x}x
• 2
• +
• x
• 2
• 1
• −2−3x+
• x
• 3
• Using the identity, (a-b)^2=a^2+b^2-2ab(a−b)
• 2
• =a
• 2
• +b
• 2
• −2ab , we have
• (x-\frac{1}{x})^2=x^2+{\frac{1}{x^2}-2
• Thus, the given equation becomes,
• x^2+{\frac{1}{x^2}}-2-3x+\frac{3}{x}=(x-\frac{1}{x})^2-3x+{\frac{3}{x}
• =(x-\frac{1}{x})^2-3(x-{\frac{1}{x}})(x−
• x
• 1
• )
• 2
• −3(x−
• x
• 1
• )
• =(x-{\frac{1}{x})(x-\frac{1}{x}-3)
• which is the required factorized

Answer 2

Answer:

There u go

Step-by-step explanation:

hope it will help you