Math, asked by pratikshachhetri6, 5 months ago

factorise:x^2+1/x^2-2x-2/x​

Answers

Answered by Nivedita4209
1

Answer:

Hope u like my process

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\begin{gathered}= > {x}^{2} + \frac{1}{ {x}^{2} } + 2 - 2x - \frac{2}{x} \\ \\ = > {x}^{2} + \frac{1}{ {x}^{2} } + 2x. \frac{1}{x} - 2(x + \frac{1}{x} ) \\ \\ = > {(x + \frac{1}{x} )}^{2} - 2(x + \frac{1}{x} ) \\ \\ = > (x + \frac{1}{x} )(x + \frac{1}{x} - 2) \\ \\ \mathcal{the \: \: required \: \: factorization \: \: is} \\ \\ = > \underline{(x + \frac{1}{x} )(x + \frac{1}{x} - 2) } \\ \\\end{gathered}=>x2+x21+2−2x−x2=>x2+x21+2x.x1−2(x+x1)=>(x+x1)2−2(x+x1)=>(x+x1)(x+x1−2)therequiredfactorizationis=>(x+x1)(x+x1−2)

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