Question

factorise x^2+1/x^2-3​

Answer 1

Answer:

x² 2+1/x²2-3

x² 2+1=x²*3

x² 2-3=x²*-1

and here

(x²+3) (x²-1)

so we use this equation

(x)²+(3-1)*x+(3)(-1)

x²-2x-3

Answer 2

Step-by-step explanation:

by using (a+b) ^2 = a^2 +2ab + b^2

$(x + (1 \div {x} ))^{2} = {x}^{2} + (1 \div {x}^{2} ) + 2$

using this we get

${x}^{2} + (1 \div {x}^{2} ) - 3 + 2 - 2 \\ \\ {x}^{2} + (1 \div {x}^{2} ) + 2 - 5 \\ \\ ({x} + (1 \div {x}))^{2} - (sqrt{5} )^{2} \\ \\ ({x} + (1 \div {x}) - \sqrt{5} )({x} + (1 \div {x}) + \sqrt{5} )$