Question

Factorise (x^2+1/x^2)-4(x+1x)+6

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Solution:

(x²+1/x²)-4(x+1/x)+6

= (x²+1/x²+2-2)-4(x+1/x)+6

= (x²+1/x²+2)-2-4(x+1/x)+6

= (x+1/x)²-4(x+1/x)+6-2

= (x+1/x)²-4(x+1/x)+4

= (x+1/x)²-2*(x+1/x)*2 + 2²

= [x+1/x-2]²

=( x+1/x-2)(x+1/x-2)

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