Factorise : (x^2 − 1)(x + 3)(x + 5) + 16
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Answer:
For this one I will merely give the answer as
(
x
−
a
)
(
x
−
b
)
(
x
2
+
c
x
+
d
)
. Use what is below to work the values out.
Explanation:
Multiplying out we have:
(
x
+
1
)
(
x
+
2
)
(
x
+
3
)
(
x
+
4
)
−
120
=
x
4
+
10
x
3
+
35
x
2
+
50
x
−
96
Can you find a pair of rational (actually, integer) zeroes of this polynomial? Hint:
120
=
2
×
3
×
4
×
5
=
(
−
5
)
×
(
−
4
)
×
(
−
3
)
×
(
−
2
)
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