factorise x^2+10x+24
Answers
Answer:
x²+10x+24
x²+6x+4x+24
x(x+6)+4(x+6)
hope it helps you...
The first term is, x2 its coefficient is 1 .
The middle term is, -10x its coefficient is -10 .
The last term, "the constant", is -24
Step-1 : Multiply the coefficient of the first term by the constant 1 • -24 = -24
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -10 .
-24 + 1 = -23
-12 + 2 = -10 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 2
x2 - 12x + 2x - 24
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-12)
Add up the last 2 terms, pulling out common factors :
2 • (x-12)
Step-5 : Add up the four terms of step 4 :
(x+2) • (x-12)
Which is the desired factorization
Final result :(x + 2) • (x - 12)