Question

factorise x^2+10x-39​

Answer 1

Answer:

X2+10x-39=0

X2+13x-3x-39=0

x(x+13)-3(x+13)=0

(x+13)(x-3)=0

x=-13 or x=3

Mark me as a brianliant

follow also

Answer 2

$\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTioN :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{x² + 10x - 39 = 0}$

$\qquad\tt{:}\longrightarrow\large\textsf{x² + 13x - 3x - 39 = 0}$

$\qquad\tt{:}\longrightarrow\large\textsf{x ( x + 13 ) - 3 ( x + 13 ) = 0}$

$\qquad\tt{:}\longrightarrow\large\textsf{( x - 3 ) ( x + 13 ) = 0}$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{x = 3 or x = - 13}}$

$\large\textsf{ }$

$\LARGE\textsf{\underline\textcolor{aqua}{↭ MoRe fOrMuLaS :-}}$

$\large\textsf{ }$

$\qquad\tt{:}\longrightarrow\large\textsf{( a + b )² = a² + b² + 2ab}$

$\qquad\tt{:}\longrightarrow\large\textsf{( a - b )² = a² + b² - 2ab}$

$\qquad\tt{:}\longrightarrow\large\textsf{a² - b² = ( a + b ) ( a - b )}$

$\qquad\tt{:}\longrightarrow\large\textsf{a² + b² = ( a + b )² - 2ab}$

$\qquad\tt{:}\longrightarrow\large\textsf{a³ + b³ = ( a + b ) ( a² - 2ab + b² )}$

$\qquad\tt{:}\longrightarrow\large\textsf{a³ - b³ = ( a - b ) ( a² + ab + b² )}$

$\qquad\tt{:}\longrightarrow\large\textsf{( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac }$

$\large\textsf{ }$