Question

factorise x^2+12x+36 using the identity (a+b)^2​

Answer 1

Answer:

For quadratic polynomials, the algorithm is as follows:

First, multiply the coefficient of the highest degree term and the constant. In this case, it is (1).(36)=36

Now, check the factors of the product and find how many different ways they can be arranged to get the product.

36=1.36

=2.18

=4.9

=6.6

=12.3

Now, you have to choose the pair of factors in such a way that adding them or subtracting them must be equal to the middle term coefficient.

We choose 6.6 because -6-6=-12 which is the coefficient of the middle term.

Now, split the middle term as -6x-6x, since the factors we chose are -6 and -6.

That is,

x

2

-6x-6x+36.

Now, take out the common factors from each pair.

That is, x(x-6)-6(x-6)

Finally, (x-6)(x-6) is the required factored form.

Thank you and have a nice day