Question

factorise x^2 -14x-120​

Answer 1

Step-by-step explanation:

a+b=−14

ab=1\left(-120\right)=-120

ab=1(−120)=−120

view step

ababa+b-120

1,-120

1,−120

2,-60

2,−60

3,-40

3,−40

4,-30

4,−30

5,-24

5,−24

6,-20

6,−20

8,-15

8,−15

10,-12

10,−12

view step

1-120=-119

1−120=−119

2-60=-58

2−60=−58

3-40=-37

3−40=−37

4-30=-26

4−30=−26

5-24=-19

5−24=−19

6-20=-14

6−20=−14

8-15=-7

8−15=−7

10-12=-2

10−12=−2

view step

-14

a=-20

a=−20

b=6

b=6

view step

x^{2}-14x-120

\left(x^{2}-20x\right)+\left(6x-120\right)

\left(x^{2}-20x\right)+\left(6x-120\right)

(x

2

−20x)+(6x−120)

view step

x6

x\left(x-20\right)+6\left(x-20\right)

x(x−20)+6(x−20)

view step

x-20

\left(x-20\right)\left(x+6\right)

(x−20)(x+6)

Next step

Answer 2

HERE YOU GO,

We have,

x^2-14x-120=0