Question

factorise x^2+17x+60 by splitting middle term​

Answer 1

Answer:

In the given polynomial x  

2

−17x+60,

The first term is x  

2

 and its coefficient is 1.

The middle term is −17x and its coefficient is −17.

The last term is a constant term 60.

Multiply the coefficient of the first term by the constant 1×60=60.

We now find the factor of 60 whose sum equals the coefficient of the middle term, which is −17 and then factorize the polynomial x  

2

−17x+60 as shown below:

 

x  

2

−17x+60

=x  

2

−12x−5x+60

=x(x−12)−5(x−12)

=(x−5)(x−12)

Hence, x  

2

−17x+60=(x−5)(x−12).

Answer 2

As we know, In splitting the middle term, we use:

ax^2 + bx + c . Wherein Product = ac and

Sum = b

In this question,

x^2 + 17x + 60 Product = 60

x^2 + 12x + 5x +60 Sum = 17

x ( x + 12) +5 ( x + 12)

(x + 12) ( x + 5) is the answer for your question

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