Question

factorise : x^2 - ( √2 + √5 ) x + √10 ​

Answer 1

x^2-(√2+√5)x+√10

a=1 b=-(√2+√5) c=√10

roots= [-b+-√b^2-4ac]/2a

={(√2+√5)+-√[(√2+√5)^2-4*1√10]}/2

={(√2+√5)+-√[(2+2√2*√5+5)-4√10]}/2

={(√2+√5)+-√[7+2√2*√5-4√10]}/2

=[(√2+√5)+-√(7+2√10-4√10)]/2

=[(√2+√5)+-√(7-2√10)]/2

roots are [(√2+√5)+√(7-2√10)]/2

and

[(√2+√5)-√(7-2√10)]/2

Answer 2

Answer:

(x - √2) (x - √5)

Step-by-step explanation:

x² - (√2 + √5)x + √10

=> x² - (√2x + √5x) + √10

=> x² - √2x - √5x + √10

=> x(x - √2) - √5(x - √2)

=> (x - √2) (x - √5)

Hence x² - (√2 + √5)x + √10 = (x - √2) (x - √5)

hope it helps.