Factorise (x+2)^2-(x+4)^2
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(X+2)^2-(X+4)^4
=x^2+4+4x-x^2-16-8x
=-12-4x
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Answered by
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Answer:
(x+2)^2 - (x + 4)^2
(x^2 +4x +4) - (x^2 + 8x +16)
x^2 + 4x + 4 - x^2 -8x - 16
-4x - 12
-4(x+3)
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