factorise x^2+20x-8000
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x squre + 20x - 8000 = 0
x square + 20x - 400 x - 800 = 0
x(x+2o) -400 (x+20) = 0
x+20 or x - 400
x = - 20 or x = + 400
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theeta:
Incorrect. we will get x^2+(-80+100)x-8000 therefore the final factorization will be (x-80)(x+100)
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Interesting Question!! ✌
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➡ x^2 + 20x - 8000
= x^2 + ( - 20 + 400 ) x - 8000
= x^2 - 20x + 400x - 8000
= x ( x - 20 ) + 400 ( x - 20 )
= ( x + 400 ) ( x - 20 )
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Correct Answer ➡ ( x + 400 ) ( x - 20 ) ✔
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Incorrect. we will get x^2+(-80+100)x-8000 therefore the final factorization will be (x-80)(x+100)
Listen, We can take x^2 + ( - 80 + 100 ) x too
As, - 80 × 100 = - 8000 ☺
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