Question

factorise x^2 - 21x+108
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Answer 1

Step-by-step explanation:

hope this answer will be helpful

Answer 2

${x}^{2} - 21x + 108$

${x}^{2} - 12x - 9x + 108$

$x(x - 12) - 9(x - 12) \\ (x - 12) \: (x - 9)$

so the factors of x are:

${\bold{\boxed{12}}}$ and ${\bold{\boxed{9}}}$