Math, asked by manendra8989, 9 months ago

Factorise x^2-22+120 by splitting up the middle term ​

Answers

Answered by rithwik68
1

x2−22x+120

factors of 1× 120 are:

60×2 , 3×40, 4×30, 5×24, 6×20, 8×15, 10×12

so now,

{x}^{2} - 10x - 12x + 120x2−10x−12x+120

( {x}^{2} - 10x) - (12x + 120)(x2−10x)−(12x+120)

x(x - 10) - 12(x - 10)x(x−10)−12(x−10)

(x - 12)( x- 10)(x−12)(x−10)

Hope this will help you!!

Please mark it as the brainliest question

Answered by kk407358
1

Answer:

(x - 10)(x - 12)

Step-by-step explanation:

x^2-22x+120

x^2-10x-12x+120

x(x-10)-12(x-10)

• (x - 10)(x - 12)

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