Math, asked by khushisongara, 11 months ago

factorise x^2-23x+132​


ankitasaloafer: x^2+12x+11x+132
ankitasaloafer: x(x+12)+11(x+12)
ankitasaloafer: x+12=0
ankitasaloafer: x+11=0
kathikasamrat59: This is wrong
ankitasaloafer: bhen ka takka....kaise??
kathikasamrat59: It's -12x-11x

Answers

Answered by PriyaReddy1234
25
Hey mate here is your answer

x^2-23x+132
x^2-12x-11x+132
x(x-12)-11(x-12)
x-11=0
x=11
(OR)
x-12=0
x=12..

Hope it helps you.....


PriyaReddy1234: ??
PriyaReddy1234: Then u reported know. will my answer delete??
PriyaReddy1234: oh tq bro
khushisongara: actually its by mistake
PriyaReddy1234: my one is also correct100%
Answered by Anonymous
26

 {x}^{2}  - 23x + 132 \\  =  \geqslant using \: middle \: term \: spirit \\  {x}^{2}  + ( - 11 - 12) + 132 \\  =  \geqslant (x - 11)(x - 12) \: ans \\  \:  \:  \:  \:  \:  \:  |regards \:  \:  -  \geqslant akshat \\  \: rajput) \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:class = 8  \:  \:  \:  \:  \: |

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