factorise x^2-2ax+a^2-b^2 by splitting the middle term
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0
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Step-by-step explanation:
Type I: Factorization of Quadratic polynomials of the form x2 + bx + c. (i) In order to factorize x2 + bx + c we have to find numbers p and q such that p + q = b and pq = c. (ii) After finding p and q, we split the middle term in the quadratic as px + qx and get desired factors by grouping the terms.
Answered by
0
Answer:
Given,
x
2
+2ax+(a
2
−b
2
)=0
or, x
2
+{(a+b)+(a−b)}x+(a−b)(a+b)=0
or, x(x+a+b)+(a−b)(x+a+b)=0
or, (x+a+b)(x+(a−b))=0
or, x=−(a+b),−(a−b).
hope I help you!!!
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