Question

factorise x^2 + 2xy + y^2 - 4z^2

Answer 1

This is your answer....

Answer 2

☆Hey Mate!!!☆

${x}^{2} + 2xy + {y}^{2} - 4 {z}^{2} \\ {(x + y)}^{2} - 4 {z}^{2} \\ {(x + y)}^{2} - {(2z)}^{2} \\ (x + y + 2z)(x + y - 2z)$

Hope it helps☺!