Question

factorise: x^2-2y+xy-4

Answer 1

Answer:

Step-by-step explanation:

x²-2y+xy-4

=x²-4+xy-2y

=(x²-2²)+xy-2y by identity x²-y²=(x-y)(x+y)

=(x-2)(x+2) +y(x-2)

=(x-2)(x+2+y)

=(x-2)(x+y+2)

Answer 2

Step-by-step explanation:

x^2 - 2y + xy -4

=(x^2-4) + (xy - 2y)

=(x+2) (x-2) +y (x-2)

=(x-2) ((x+2)+y)

=(x-2) (x+y+2)