Math, asked by Nathiya475, 11 months ago

Factorise x^2 - 31x + 220.

Answers

Answered by sonabrainly
3

Simplifying

x2 + -31x + 220 = 0


Reorder the terms:

220 + -31x + x2 = 0


Solving

220 + -31x + x2 = 0


Solving for variable 'x'.


Factor a trinomial.

(11 + -1x)(20 + -1x) = 0


Subproblem 1

Set the factor '(11 + -1x)' equal to zero and attempt to solve:


Simplifying

11 + -1x = 0


Solving

11 + -1x = 0


Move all terms containing x to the left, all other terms to the right.


Add '-11' to each side of the equation.

11 + -11 + -1x = 0 + -11


Combine like terms: 11 + -11 = 0

0 + -1x = 0 + -11

-1x = 0 + -11


Combine like terms: 0 + -11 = -11

-1x = -11


Divide each side by '-1'.

x = 11


Simplifying

x = 11

Subproblem 2

Set the factor '(20 + -1x)' equal to zero and attempt to solve:


Simplifying

20 + -1x = 0


Solving

20 + -1x = 0


Move all terms containing x to the left, all other terms to the right.


Add '-20' to each side of the equation.

20 + -20 + -1x = 0 + -20


Combine like terms: 20 + -20 = 0

0 + -1x = 0 + -20

-1x = 0 + -20


Combine like terms: 0 + -20 = -20

-1x = -20


Divide each side by '-1'.

x = 20


Simplifying

x = 20

Solution

x = {11, 20}

Answered by Anonymous
12

 {x}^{2}  - 31x + 220  \\ write \: 31x \: as \: a \: difference \:\\  {x}^{2}  - 11x - 20x + 220 \\ factor \: out \: x \: from \: the \: expression \\ x(x - 11) - 20x + 220 \\ factor \: out \:  - 20 \: from \: the \: expression \\ x(x - 11) - 20( x - 11) \\ (x - 11)(x - 20)
Hope it will help you
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