Question

Factorise x^2-3x+1.

Answer 1

Answer:

Factorization:

This quadratic equation cannot be solved by normal method need to use following formula

X = (-b ± √b^2 -4ac)/2a

X^2 - 3X + 1 = 0

In this case,

a= 1

b = -3

c =1

X = (3±√9–4)/2

=(3±√5)/2

= (3±2.24)/2

X = (3+2.24)/2 , (3–2.24)/2

X = 5.24/2 , 0.76/2

Roots X = 2.62, 0.38

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# ItzYourQueen01

Answer 2

Answer:

Hope it's helpful for you

Step-by-step explanation:

${x}^{2} - 3x + 1$

$x = \frac{ - b \frac{ + }{ - } \sqrt{ {b }^{2} } -4ac }{2a}$

$given.$

$a = 1 \\ b = - 3 \\ c = 1$

$x = \binom{3 \frac{ + }{ - } \sqrt{9} - 4 }{2}$

$= \binom{3 \frac{ + }{ - } \sqrt{5} }{2}$

$= ( \frac{3 \frac{ + }{ - } 2.24}{2} )$

$x = ( \frac{3 + 2.24}{2} ) \: \: ( \frac{3 - 2.24}{2} )$

$x = \frac{5.24}{2} \: \: \: \frac{0.76}{2}$

$x = 2.26 \: and \: 0.38$

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